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Having trouble setting up the bounds for theta in this situation z is bounded by 0 to 1 an r is bounded 0 to sqrt(2) but we realized that because the of the bounded region it is not a simple 0 to 2pi. Theta is also cut down because of the Z being only from 0 to 1 which cuts off part of the radius. We know it is something less the pi/2 but do not know what, so what do we do to find the region in which theta is bounded?
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I guess you mean this problem?
Between y=0 and y=sqrt(2-x^2) is the half circle in the upper half plane of radius sqrt(2)--that makes theta run from 0 to pi. z between 0 and 1 has nothing to do with it.
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