did green's theorem for the
entire figure as if it was closed, then subtracted the AD portion with a
simple line intergral and got 18 for the area of the trapezoid, and got
81/2 for the AD integral.
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As you didn't say but I suppose you know ∂Q/∂x-∂P/∂y=9-8=1, so the integral counterclockwise around the closed path is equal to the area. This means, as you know, that the integral ABCD plus the integral DA is equal to the area. In other words it's the area minus the integral DA is equal to the integral of ABCD, which is the same as the area PLUS the integral AD: the correct answer is
18+(81/2).
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